Oracle 1z1-809 Actual Free Exam Questions & Community Discussion
Given that these files exist and are accessible:

and given the code fragment:

Which code fragment can be inserted at line n1 to enable the code to print only /company/emp?

and given the code fragment:

Which code fragment can be inserted at line n1 to enable the code to print only /company/emp?
Correct Answer: D
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For which three objects must a vendor provide implementations in its JDBC driver? (Choose three.)
Correct Answer: B,C,F
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Given the code fragment:
List<String> empDetails = Arrays.asList("100, Robin, HR", "200, Mary, AdminServices","101, Peter, HR"); empDetails.stream()
.filter(s-> s.contains("r"))
.sorted()
.forEach(System.out::println); //line n1
What is the result?
List<String> empDetails = Arrays.asList("100, Robin, HR", "200, Mary, AdminServices","101, Peter, HR"); empDetails.stream()
.filter(s-> s.contains("r"))
.sorted()
.forEach(System.out::println); //line n1
What is the result?
Correct Answer: C
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Given the structure of the Student table:
Student (id INTEGER, name VARCHAR)
Given the records from the STUDENT table:

Given the code fragment:

Assume that:
What is the result?
Student (id INTEGER, name VARCHAR)
Given the records from the STUDENT table:

Given the code fragment:

Assume that:
What is the result?
Correct Answer: A
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Given the code fragments:
class Employee {
Optional<Address> address;
Employee (Optional<Address> address) {
this.address = address;
}
public Optional<Address> getAddress() { return address; }
}
class Address {
String city = "New York";
public String getCity { return city: }
public String toString() {
return city;
}
}
and
Address address = new Address;
Optional<Address> addrs1 = Optional.ofNullable (address);
Employee e1 = new Employee (addrs1);
String eAddress = (addrs1.isPresent()) ? addrs1.get().getCity() : "City Not available"; System.out.println(eAddress); What is the result?
class Employee {
Optional<Address> address;
Employee (Optional<Address> address) {
this.address = address;
}
public Optional<Address> getAddress() { return address; }
}
class Address {
String city = "New York";
public String getCity { return city: }
public String toString() {
return city;
}
}
and
Address address = new Address;
Optional<Address> addrs1 = Optional.ofNullable (address);
Employee e1 = new Employee (addrs1);
String eAddress = (addrs1.isPresent()) ? addrs1.get().getCity() : "City Not available"; System.out.println(eAddress); What is the result?
Correct Answer: C
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Given the code fragment:
9. Connection conn = DriveManager.getConnection(dbURL, userName, passWord);
10. String query = "SELECT id FROM Employee";
11. try (Statement stmt = conn.createStatement()) {
12. ResultSet rs = stmt.executeQuery(query);
13.stmt.executeQuery("SELECT id FROM Customer");
14. while (rs.next()) {
15. //process the results
16.System.out.println("Employee ID: "+ rs.getInt("id"));
17.}
18. } catch (Exception e) {
19. System.out.println ("Error");
20. }
Assume that:
The required database driver is configured in the classpath.
The appropriate database is accessible with the dbURL, userName, and passWord exists.
The Employee and Customer tables are available and each table has id column with a few records and the SQL queries are valid.
What is the result of compiling and executing this code fragment?
9. Connection conn = DriveManager.getConnection(dbURL, userName, passWord);
10. String query = "SELECT id FROM Employee";
11. try (Statement stmt = conn.createStatement()) {
12. ResultSet rs = stmt.executeQuery(query);
13.stmt.executeQuery("SELECT id FROM Customer");
14. while (rs.next()) {
15. //process the results
16.System.out.println("Employee ID: "+ rs.getInt("id"));
17.}
18. } catch (Exception e) {
19. System.out.println ("Error");
20. }
Assume that:
The required database driver is configured in the classpath.
The appropriate database is accessible with the dbURL, userName, and passWord exists.
The Employee and Customer tables are available and each table has id column with a few records and the SQL queries are valid.
What is the result of compiling and executing this code fragment?
Correct Answer: B
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Given the code fragments:
class Caller implements Callable<String> {
String str;
public Caller (String s) {this.str=s;}
public String call()throws Exception { return str.concat ("Caller");}
}
class Runner implements Runnable {
String str;
public Runner (String s) {this.str=s;}
public void run () { System.out.println (str.concat ("Runner"));}
}
and
public static void main (String[] args) InterruptedException, ExecutionException { ExecutorService es = Executors.newFixedThreadPool(2); Future f1 = es.submit (new Caller ("Call")); Future f2 = es.submit (new Runner ("Run")); String str1 = (String) f1.get(); String str2 = (String) f2.get();//line n1 System.out.println(str1+ ":" + str2);
}
What is the result?
class Caller implements Callable<String> {
String str;
public Caller (String s) {this.str=s;}
public String call()throws Exception { return str.concat ("Caller");}
}
class Runner implements Runnable {
String str;
public Runner (String s) {this.str=s;}
public void run () { System.out.println (str.concat ("Runner"));}
}
and
public static void main (String[] args) InterruptedException, ExecutionException { ExecutorService es = Executors.newFixedThreadPool(2); Future f1 = es.submit (new Caller ("Call")); Future f2 = es.submit (new Runner ("Run")); String str1 = (String) f1.get(); String str2 = (String) f2.get();//line n1 System.out.println(str1+ ":" + str2);
}
What is the result?
Correct Answer: A
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Given:

What change should you make to guarantee a single order of execution (printed values 1 -100 in order)?

What change should you make to guarantee a single order of execution (printed values 1 -100 in order)?
Correct Answer: D
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Given the code fragment:
BiFunction<Integer, Double, Integer> val = (t1, t2) -> t1 + t2; //line n1
//line n2
System.out.println(val.apply(10, 10.5));
What is the result?
BiFunction<Integer, Double, Integer> val = (t1, t2) -> t1 + t2; //line n1
//line n2
System.out.println(val.apply(10, 10.5));
What is the result?
Correct Answer: B
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Given the code fragments:
class Employee {
Optional<Address> address;
Employee (Optional<Address> address) {
this.address = address;
}
public Optional<Address> getAddress() { return address; }
}
class Address {
String city = "New York";
public String getCity { return city: }
public String toString() {
return city;
}
}
and
Address address = null;
Optional<Address> addrs1 = Optional.ofNullable (address);
Employee e1 = new Employee (addrs1);
String eAddress = (addrs1.isPresent()) ? addrs1.get().getCity() : "City Not available"; What is the result?
class Employee {
Optional<Address> address;
Employee (Optional<Address> address) {
this.address = address;
}
public Optional<Address> getAddress() { return address; }
}
class Address {
String city = "New York";
public String getCity { return city: }
public String toString() {
return city;
}
}
and
Address address = null;
Optional<Address> addrs1 = Optional.ofNullable (address);
Employee e1 = new Employee (addrs1);
String eAddress = (addrs1.isPresent()) ? addrs1.get().getCity() : "City Not available"; What is the result?
Correct Answer: B
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